Base | Representation |
---|---|
bin | 1100001111010011010111… |
… | …0000100111111001101011 |
3 | 1202122110221212111112110101 |
4 | 3003310311300213321223 |
5 | 3230440001311232123 |
6 | 44342024251330231 |
7 | 2556144600511054 |
oct | 303646560477153 |
9 | 52573855445411 |
10 | 13457034477163 |
11 | 4319107157a32 |
12 | 1614091750977 |
13 | 767cba5511a4 |
14 | 347476c8b72b |
15 | 1850ad29eaad |
hex | c3d35c27e6b |
13457034477163 has 2 divisors, whose sum is σ = 13457034477164. Its totient is φ = 13457034477162.
The previous prime is 13457034477143. The next prime is 13457034477193. The reversal of 13457034477163 is 36177443075431.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13457034477163 - 213 = 13457034468971 is a prime.
It is not a weakly prime, because it can be changed into another prime (13457034477143) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6728517238581 + 6728517238582.
It is an arithmetic number, because the mean of its divisors is an integer number (6728517238582).
Almost surely, 213457034477163 is an apocalyptic number.
13457034477163 is a deficient number, since it is larger than the sum of its proper divisors (1).
13457034477163 is an equidigital number, since it uses as much as digits as its factorization.
13457034477163 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 17781120, while the sum is 55.
The spelling of 13457034477163 in words is "thirteen trillion, four hundred fifty-seven billion, thirty-four million, four hundred seventy-seven thousand, one hundred sixty-three".
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