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13460105340067 is a prime number
BaseRepresentation
bin1100001111011110110011…
…0011000010010010100011
31202122202212212212112102111
43003313230303002102203
53231012243431340232
644343253110500151
72556313646433121
oct303675463022243
952582785775374
1013460105340067
11431a442618761
1216147aa064657
13768389816c29
14347688a5c911
151851dcb90047
hexc3deccc24a3

13460105340067 has 2 divisors, whose sum is σ = 13460105340068. Its totient is φ = 13460105340066.

The previous prime is 13460105340049. The next prime is 13460105340191. The reversal of 13460105340067 is 76004350106431.

13460105340067 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is an emirp because it is prime and its reverse (76004350106431) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13460105340067 - 211 = 13460105338019 is a prime.

It is a super-3 number, since 3×134601053400673 (a number of 40 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (13460105340667) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6730052670033 + 6730052670034.

It is an arithmetic number, because the mean of its divisors is an integer number (6730052670034).

Almost surely, 213460105340067 is an apocalyptic number.

13460105340067 is a deficient number, since it is larger than the sum of its proper divisors (1).

13460105340067 is an equidigital number, since it uses as much as digits as its factorization.

13460105340067 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 181440, while the sum is 40.

Adding to 13460105340067 its reverse (76004350106431), we get a palindrome (89464455446498).

The spelling of 13460105340067 in words is "thirteen trillion, four hundred sixty billion, one hundred five million, three hundred forty thousand, sixty-seven".