Base | Representation |
---|---|
bin | 10011100101100101001… |
… | …100100111100000111001 |
3 | 11202200022121221020200022 |
4 | 103211211030213200321 |
5 | 134023123234220131 |
6 | 2510204303020225 |
7 | 166150460032412 |
oct | 23454514474071 |
9 | 4680277836608 |
10 | 1346022570041 |
11 | 479932717246 |
12 | 198a5029a675 |
13 | 99c10b188c6 |
14 | 4920d95c809 |
15 | 2502e50237b |
hex | 13965327839 |
1346022570041 has 4 divisors (see below), whose sum is σ = 1346695920000. Its totient is φ = 1345349220084.
The previous prime is 1346022569987. The next prime is 1346022570043. The reversal of 1346022570041 is 1400752206431.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 1346022570041 - 230 = 1344948828217 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1346022569983 and 1346022570010.
It is not an unprimeable number, because it can be changed into a prime (1346022570043) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 336671981 + ... + 336675978.
It is an arithmetic number, because the mean of its divisors is an integer number (336673980000).
Almost surely, 21346022570041 is an apocalyptic number.
It is an amenable number.
1346022570041 is a deficient number, since it is larger than the sum of its proper divisors (673349959).
1346022570041 is an equidigital number, since it uses as much as digits as its factorization.
1346022570041 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 673349958.
The product of its (nonzero) digits is 40320, while the sum is 35.
Adding to 1346022570041 its reverse (1400752206431), we get a palindrome (2746774776472).
The spelling of 1346022570041 in words is "one trillion, three hundred forty-six billion, twenty-two million, five hundred seventy thousand, forty-one".
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