1400752206431 has 2 divisors, whose sum is σ = 1400752206432. Its totient is φ = 1400752206430.

The previous prime is 1400752206419. The next prime is 1400752206433. The reversal of 1400752206431 is 1346022570041.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1400752206431 - 2¹⁰ = 1400752205407 is a prime.

It is a super-3 number, since 3×1400752206431³ (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

Together with 1400752206433, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 1400752206391 and 1400752206400.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1400752206433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 700376103215 + 700376103216.

It is an arithmetic number, because the mean of its divisors is an integer number (700376103216).

Almost surely, 2^{1400752206431} is an apocalyptic number.

1400752206431 is a deficient number, since it is larger than the sum of its proper divisors (1).

1400752206431 is an equidigital number, since it uses as much as digits as its factorization.

1400752206431 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 40320, while the sum is 35.

Adding to 1400752206431 its reverse (1346022570041), we get a palindrome (2746774776472).

The spelling of 1400752206431 in words is "one trillion, four hundred billion, seven hundred fifty-two million, two hundred six thousand, four hundred thirty-one".