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1346146000141 = 4714728552103
BaseRepresentation
bin10011100101101100100…
…011011101110100001101
311202200122020012010221111
4103211230203131310031
5134023401334001031
62510224432332021
7166153516131055
oct23455443356415
94680566163844
101346146000141
11479996361098
12198a856a4011
1399c30573b77
14492220cc565
152503a2841b1
hex1396c8ddd0d

1346146000141 has 4 divisors (see below), whose sum is σ = 1346174599392. Its totient is φ = 1346117400892.

The previous prime is 1346146000117. The next prime is 1346146000207. The reversal of 1346146000141 is 1410006416431.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1346146000141 - 215 = 1346145967373 is a prime.

It is a super-2 number, since 2×13461460001412 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1346146000541) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14228905 + ... + 14323198.

It is an arithmetic number, because the mean of its divisors is an integer number (336543649848).

Almost surely, 21346146000141 is an apocalyptic number.

It is an amenable number.

1346146000141 is a deficient number, since it is larger than the sum of its proper divisors (28599251).

1346146000141 is an equidigital number, since it uses as much as digits as its factorization.

1346146000141 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 28599250.

The product of its (nonzero) digits is 6912, while the sum is 31.

The spelling of 1346146000141 in words is "one trillion, three hundred forty-six billion, one hundred forty-six million, one hundred forty-one", and thus it is an aban number.

Divisors: 1 47147 28552103 1346146000141