Base | Representation |
---|---|
bin | 111110101100101011… |
… | …0110000110110010011 |
3 | 110212112111210110121112 |
4 | 1331121112300312103 |
5 | 4201222120010101 |
6 | 141504301243535 |
7 | 12504403453556 |
oct | 1753126606623 |
9 | 425474713545 |
10 | 134643125651 |
11 | 52113597161 |
12 | 221178635ab |
13 | c909b11268 |
14 | 6733dd069d |
15 | 37807c46bb |
hex | 1f595b0d93 |
134643125651 has 2 divisors, whose sum is σ = 134643125652. Its totient is φ = 134643125650.
The previous prime is 134643125641. The next prime is 134643125657. The reversal of 134643125651 is 156521346431.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-134643125651 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 134643125599 and 134643125608.
It is not a weakly prime, because it can be changed into another prime (134643125657) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67321562825 + 67321562826.
It is an arithmetic number, because the mean of its divisors is an integer number (67321562826).
Almost surely, 2134643125651 is an apocalyptic number.
134643125651 is a deficient number, since it is larger than the sum of its proper divisors (1).
134643125651 is an equidigital number, since it uses as much as digits as its factorization.
134643125651 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 259200, while the sum is 41.
The spelling of 134643125651 in words is "one hundred thirty-four billion, six hundred forty-three million, one hundred twenty-five thousand, six hundred fifty-one".
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