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1346789002393 is a prime number
BaseRepresentation
bin10011100110010010111…
…000010100110010011001
311202202022001010001012201
4103212102320110302121
5134031210441034033
62510412322210201
7166205454431152
oct23462270246231
94682261101181
101346789002393
1147a19631020a
12199024ab3961
139a003847983
144928366a929
152507694847d
hex13992e14c99

1346789002393 has 2 divisors, whose sum is σ = 1346789002394. Its totient is φ = 1346789002392.

The previous prime is 1346789002333. The next prime is 1346789002439. The reversal of 1346789002393 is 3932009876431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1057633298569 + 289155703824 = 1028413^2 + 537732^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1346789002393 is a prime.

It is not a weakly prime, because it can be changed into another prime (1346789002333) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 673394501196 + 673394501197.

It is an arithmetic number, because the mean of its divisors is an integer number (673394501197).

Almost surely, 21346789002393 is an apocalyptic number.

It is an amenable number.

1346789002393 is a deficient number, since it is larger than the sum of its proper divisors (1).

1346789002393 is an equidigital number, since it uses as much as digits as its factorization.

1346789002393 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5878656, while the sum is 55.

The spelling of 1346789002393 in words is "one trillion, three hundred forty-six billion, seven hundred eighty-nine million, two thousand, three hundred ninety-three".