Base | Representation |
---|---|
bin | 111110101110101011… |
… | …1101011111000100011 |
3 | 110212201012112020100212 |
4 | 1331131113223320203 |
5 | 4201341340220243 |
6 | 141515105004335 |
7 | 12506152104323 |
oct | 1753527537043 |
9 | 425635466325 |
10 | 134710476323 |
11 | 52148608775 |
12 | 221363236ab |
13 | c91aa62c27 |
14 | 673cd23283 |
15 | 378667a318 |
hex | 1f5d5ebe23 |
134710476323 has 2 divisors, whose sum is σ = 134710476324. Its totient is φ = 134710476322.
The previous prime is 134710476283. The next prime is 134710476361. The reversal of 134710476323 is 323674017431.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-134710476323 is a prime.
It is a super-3 number, since 3×1347104763233 (a number of 34 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (134710476023) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67355238161 + 67355238162.
It is an arithmetic number, because the mean of its divisors is an integer number (67355238162).
Almost surely, 2134710476323 is an apocalyptic number.
134710476323 is a deficient number, since it is larger than the sum of its proper divisors (1).
134710476323 is an equidigital number, since it uses as much as digits as its factorization.
134710476323 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 254016, while the sum is 41.
The spelling of 134710476323 in words is "one hundred thirty-four billion, seven hundred ten million, four hundred seventy-six thousand, three hundred twenty-three".
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