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1347204113 is a prime number
BaseRepresentation
bin101000001001100…
…1011010000010001
310110220000001121122
41100103023100101
510224341012423
6341403132025
745246021533
oct12023132021
93426001548
101347204113
11631509432
12317214015
131861548c8
14caccb853
157d4168c8
hex504cb411

1347204113 has 2 divisors, whose sum is σ = 1347204114. Its totient is φ = 1347204112.

The previous prime is 1347204073. The next prime is 1347204127. The reversal of 1347204113 is 3114027431.

1347204113 is nontrivially palindromic in base 8.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 840594049 + 506610064 = 28993^2 + 22508^2 .

It is a cyclic number.

It is not a de Polignac number, because 1347204113 - 28 = 1347203857 is a prime.

It is not a weakly prime, because it can be changed into another prime (1347204163) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 673602056 + 673602057.

It is an arithmetic number, because the mean of its divisors is an integer number (673602057).

Almost surely, 21347204113 is an apocalyptic number.

It is an amenable number.

1347204113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1347204113 is an equidigital number, since it uses as much as digits as its factorization.

1347204113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2016, while the sum is 26.

The square root of 1347204113 is about 36704.2792191864. The cubic root of 1347204113 is about 1104.4459492522.

The spelling of 1347204113 in words is "one billion, three hundred forty-seven million, two hundred four thousand, one hundred thirteen".