Base | Representation |
---|---|
bin | 111110110000000000… |
… | …1001101101100100001 |
3 | 110212211022011001201112 |
4 | 1331200001031230201 |
5 | 4201434224322103 |
6 | 141523333313105 |
7 | 12510231616403 |
oct | 1754001155441 |
9 | 425738131645 |
10 | 134754917153 |
11 | 5217070182a |
12 | 22149195795 |
13 | c927022b8c |
14 | 6744bb0b73 |
15 | 378a507cd8 |
hex | 1f6004db21 |
134754917153 has 2 divisors, whose sum is σ = 134754917154. Its totient is φ = 134754917152.
The previous prime is 134754917147. The next prime is 134754917299. The reversal of 134754917153 is 351719457431.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 133095821329 + 1659095824 = 364823^2 + 40732^2 .
It is a cyclic number.
It is not a de Polignac number, because 134754917153 - 214 = 134754900769 is a prime.
It is not a weakly prime, because it can be changed into another prime (134754917113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67377458576 + 67377458577.
It is an arithmetic number, because the mean of its divisors is an integer number (67377458577).
Almost surely, 2134754917153 is an apocalyptic number.
It is an amenable number.
134754917153 is a deficient number, since it is larger than the sum of its proper divisors (1).
134754917153 is an equidigital number, since it uses as much as digits as its factorization.
134754917153 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1587600, while the sum is 50.
The spelling of 134754917153 in words is "one hundred thirty-four billion, seven hundred fifty-four million, nine hundred seventeen thousand, one hundred fifty-three".
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