Base | Representation |
---|---|
bin | 11001000110011110… |
… | …00110010100101011 |
3 | 1021210011120220110012 |
4 | 30203033012110223 |
5 | 210044333000012 |
6 | 10105114442135 |
7 | 654643432655 |
oct | 144317062453 |
9 | 37704526405 |
10 | 13476062507 |
11 | 5795982246 |
12 | 274113334b |
13 | 1369bc53ab |
14 | 91ba8d6d5 |
15 | 53d13c622 |
hex | 3233c652b |
13476062507 has 2 divisors, whose sum is σ = 13476062508. Its totient is φ = 13476062506.
The previous prime is 13476062473. The next prime is 13476062513. The reversal of 13476062507 is 70526067431.
13476062507 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13476062507 - 216 = 13475996971 is a prime.
It is a super-2 number, since 2×134760625072 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13476062407) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6738031253 + 6738031254.
It is an arithmetic number, because the mean of its divisors is an integer number (6738031254).
Almost surely, 213476062507 is an apocalyptic number.
13476062507 is a deficient number, since it is larger than the sum of its proper divisors (1).
13476062507 is an equidigital number, since it uses as much as digits as its factorization.
13476062507 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 211680, while the sum is 41.
The spelling of 13476062507 in words is "thirteen billion, four hundred seventy-six million, sixty-two thousand, five hundred seven".
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