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13479615313601 is a prime number
BaseRepresentation
bin1100010000100111011110…
…1011101011011011000001
31202201122020120022212201212
43010021313223223123001
53231322223010013401
644400241053135505
72560604301452333
oct304116753533301
952648216285655
1013479615313601
114327744482628
121618533a8a595
1376a17881c278
143485b9c27453
151859808b2dbb
hexc4277aeb6c1

13479615313601 has 2 divisors, whose sum is σ = 13479615313602. Its totient is φ = 13479615313600.

The previous prime is 13479615313579. The next prime is 13479615313613. The reversal of 13479615313601 is 10631351697431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11705457912976 + 1774157400625 = 3421324^2 + 1331975^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13479615313601 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 13479615313601.

It is not a weakly prime, because it can be changed into another prime (13479615313631) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6739807656800 + 6739807656801.

It is an arithmetic number, because the mean of its divisors is an integer number (6739807656801).

Almost surely, 213479615313601 is an apocalyptic number.

It is an amenable number.

13479615313601 is a deficient number, since it is larger than the sum of its proper divisors (1).

13479615313601 is an equidigital number, since it uses as much as digits as its factorization.

13479615313601 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1224720, while the sum is 50.

The spelling of 13479615313601 in words is "thirteen trillion, four hundred seventy-nine billion, six hundred fifteen million, three hundred thirteen thousand, six hundred one".