Base | Representation |
---|---|
bin | 10011100111011011001… |
… | …001010001011000101001 |
3 | 11202212102112110110011212 |
4 | 103213123021101120221 |
5 | 134041201324420312 |
6 | 2511132512202505 |
7 | 166250505612101 |
oct | 23473311213051 |
9 | 4685375413155 |
10 | 1348001404457 |
11 | 47a758717894 |
12 | 199302b39435 |
13 | 9a167a92146 |
14 | 4935a6a8201 |
15 | 250e80d3822 |
hex | 139db251629 |
1348001404457 has 2 divisors, whose sum is σ = 1348001404458. Its totient is φ = 1348001404456.
The previous prime is 1348001404447. The next prime is 1348001404481. The reversal of 1348001404457 is 7544041008431.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1339530779161 + 8470625296 = 1157381^2 + 92036^2 .
It is a cyclic number.
It is not a de Polignac number, because 1348001404457 - 214 = 1348001388073 is a prime.
It is a super-4 number, since 4×13480014044574 (a number of 50 digits) contains 4444 as substring.
It is not a weakly prime, because it can be changed into another prime (1348001404417) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 674000702228 + 674000702229.
It is an arithmetic number, because the mean of its divisors is an integer number (674000702229).
Almost surely, 21348001404457 is an apocalyptic number.
It is an amenable number.
1348001404457 is a deficient number, since it is larger than the sum of its proper divisors (1).
1348001404457 is an equidigital number, since it uses as much as digits as its factorization.
1348001404457 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 215040, while the sum is 41.
The spelling of 1348001404457 in words is "one trillion, three hundred forty-eight billion, one million, four hundred four thousand, four hundred fifty-seven".
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