Base | Representation |
---|---|
bin | 1100010000101010000011… |
… | …1000100010010001100011 |
3 | 1202201201000202000022121202 |
4 | 3010022200320202101203 |
5 | 3231330131434043414 |
6 | 44400433424511415 |
7 | 2560630364043362 |
oct | 304124070422143 |
9 | 52651022008552 |
10 | 13480306549859 |
11 | 4327a69686666 |
12 | 16186a747b56b |
13 | 76a258ab06c6 |
14 | 34864395d7d9 |
15 | 1859c14039de |
hex | c42a0e22463 |
13480306549859 has 2 divisors, whose sum is σ = 13480306549860. Its totient is φ = 13480306549858.
The previous prime is 13480306549849. The next prime is 13480306549939. The reversal of 13480306549859 is 95894560308431.
It is a weak prime.
It is an emirp because it is prime and its reverse (95894560308431) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13480306549859 - 212 = 13480306545763 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13480306549795 and 13480306549804.
It is not a weakly prime, because it can be changed into another prime (13480306549819) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6740153274929 + 6740153274930.
It is an arithmetic number, because the mean of its divisors is an integer number (6740153274930).
Almost surely, 213480306549859 is an apocalyptic number.
13480306549859 is a deficient number, since it is larger than the sum of its proper divisors (1).
13480306549859 is an equidigital number, since it uses as much as digits as its factorization.
13480306549859 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 111974400, while the sum is 65.
The spelling of 13480306549859 in words is "thirteen trillion, four hundred eighty billion, three hundred six million, five hundred forty-nine thousand, eight hundred fifty-nine".
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