13483655402253 has 32 divisors (see below), whose sum is σ = 18221768294400. Its totient is φ = 8867527084416.

The previous prime is 13483655402207. The next prime is 13483655402351. The reversal of 13483655402253 is 35220455638431.

It is a de Polignac number, because none of the positive numbers 2^k-13483655402253 is a prime.

It is a super-2 number, since 2×13483655402253² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13483655402196 and 13483655402205.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13483655402753) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1683558913 + ... + 1683566921.

It is an arithmetic number, because the mean of its divisors is an integer number (569430259200).

Almost surely, 2^{13483655402253} is an apocalyptic number.

It is an amenable number.

13483655402253 is a deficient number, since it is larger than the sum of its proper divisors (4738112892147).

13483655402253 is a wasteful number, since it uses less digits than its factorization.

13483655402253 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 13441.

The product of its (nonzero) digits is 10368000, while the sum is 51.

The spelling of 13483655402253 in words is "thirteen trillion, four hundred eighty-three billion, six hundred fifty-five million, four hundred two thousand, two hundred fifty-three".