Base | Representation |
---|---|
bin | 111110110010111101… |
… | …0100110011111000001 |
3 | 110220002012022012221002 |
4 | 1331211322212133001 |
5 | 4202140041100402 |
6 | 141541225541345 |
7 | 12512542533503 |
oct | 1754572463701 |
9 | 426065265832 |
10 | 134853846977 |
11 | 52211532213 |
12 | 22176344855 |
13 | c941680535 |
14 | 6753da3d73 |
15 | 379404a602 |
hex | 1f65ea67c1 |
134853846977 has 2 divisors, whose sum is σ = 134853846978. Its totient is φ = 134853846976.
The previous prime is 134853846973. The next prime is 134853846991. The reversal of 134853846977 is 779648358431.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 105128983696 + 29724863281 = 324236^2 + 172409^2 .
It is a cyclic number.
It is not a de Polignac number, because 134853846977 - 22 = 134853846973 is a prime.
It is a super-2 number, since 2×1348538469772 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (134853846973) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67426923488 + 67426923489.
It is an arithmetic number, because the mean of its divisors is an integer number (67426923489).
Almost surely, 2134853846977 is an apocalyptic number.
It is an amenable number.
134853846977 is a deficient number, since it is larger than the sum of its proper divisors (1).
134853846977 is an equidigital number, since it uses as much as digits as its factorization.
134853846977 is an evil number, because the sum of its binary digits is even.
The product of its digits is 121927680, while the sum is 65.
The spelling of 134853846977 in words is "one hundred thirty-four billion, eight hundred fifty-three million, eight hundred forty-six thousand, nine hundred seventy-seven".
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