13487624277255 has 24 divisors (see below), whose sum is σ = 24132695483520. Its totient is φ = 6961354464960.

The previous prime is 13487624277233. The next prime is 13487624277277. The reversal of 13487624277255 is 55277242678431.

13487624277255 is a `hidden beast` number, since 1 + 3 + 4 + 8 + 76 + 242 + 77 + 255 = 666.

It is an interprime number because it is at equal distance from previous prime (13487624277233) and next prime (13487624277277).

It is not a de Polignac number, because 13487624277255 - 2⁵ = 13487624277223 is a prime.

It is a super-2 number, since 2×13487624277255² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13487624277192 and 13487624277201.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 4834272540 + ... + 4834275329.

It is an arithmetic number, because the mean of its divisors is an integer number (1005528978480).

Almost surely, 2^{13487624277255} is an apocalyptic number.

13487624277255 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

13487624277255 is a deficient number, since it is larger than the sum of its proper divisors (10645071206265).

13487624277255 is a wasteful number, since it uses less digits than its factorization.

13487624277255 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9668547911 (or 9668547908 counting only the distinct ones).

The product of its digits is 158054400, while the sum is 63.

The spelling of 13487624277255 in words is "thirteen trillion, four hundred eighty-seven billion, six hundred twenty-four million, two hundred seventy-seven thousand, two hundred fifty-five".