Base | Representation |
---|---|
bin | 11001001000000001… |
… | …11101010100000001 |
3 | 1021211002011221112011 |
4 | 30210000331110001 |
5 | 210111204222201 |
6 | 10110302532521 |
7 | 655162510534 |
oct | 144400752401 |
9 | 37732157464 |
10 | 13489132801 |
11 | 57a229a141 |
12 | 2745597141 |
13 | 136c8205b1 |
14 | 91d6d2a1b |
15 | 53e370151 |
hex | 32403d501 |
13489132801 has 2 divisors, whose sum is σ = 13489132802. Its totient is φ = 13489132800.
The previous prime is 13489132781. The next prime is 13489132807. The reversal of 13489132801 is 10823198431.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 13242485776 + 246647025 = 115076^2 + 15705^2 .
It is a cyclic number.
It is not a de Polignac number, because 13489132801 - 231 = 11341649153 is a prime.
It is not a weakly prime, because it can be changed into another prime (13489132807) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6744566400 + 6744566401.
It is an arithmetic number, because the mean of its divisors is an integer number (6744566401).
Almost surely, 213489132801 is an apocalyptic number.
It is an amenable number.
13489132801 is a deficient number, since it is larger than the sum of its proper divisors (1).
13489132801 is an equidigital number, since it uses as much as digits as its factorization.
13489132801 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 41472, while the sum is 40.
The spelling of 13489132801 in words is "thirteen billion, four hundred eighty-nine million, one hundred thirty-two thousand, eight hundred one".
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