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1348925603 is a prime number
BaseRepresentation
bin101000001100110…
…1111100010100011
310111000020112001112
41100121233202203
510230311104403
6341504053535
745266451464
oct12031574243
93430215045
101348925603
11632484853
123179042ab
1318660833c
14cb218d6b
157d6569d8
hex5066f8a3

1348925603 has 2 divisors, whose sum is σ = 1348925604. Its totient is φ = 1348925602.

The previous prime is 1348925581. The next prime is 1348925621. The reversal of 1348925603 is 3065298431.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1348925603 - 210 = 1348924579 is a prime.

It is a Sophie Germain prime.

It is not a weakly prime, because it can be changed into another prime (1348925693) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 674462801 + 674462802.

It is an arithmetic number, because the mean of its divisors is an integer number (674462802).

Almost surely, 21348925603 is an apocalyptic number.

1348925603 is a deficient number, since it is larger than the sum of its proper divisors (1).

1348925603 is an equidigital number, since it uses as much as digits as its factorization.

1348925603 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 155520, while the sum is 41.

The square root of 1348925603 is about 36727.7225403373. The cubic root of 1348925603 is about 1104.9161782680.

The spelling of 1348925603 in words is "one billion, three hundred forty-eight million, nine hundred twenty-five thousand, six hundred three".