Base | Representation |
---|---|
bin | 1100010001001011011110… |
… | …1010000100000000101001 |
3 | 1202202120012000102222121012 |
4 | 3010102313222010000221 |
5 | 3232002020303111231 |
6 | 44404520010153305 |
7 | 2561365616655206 |
oct | 304226752040051 |
9 | 52676160388535 |
10 | 13489278566441 |
11 | 43308530a44a7 |
12 | 161a390122835 |
13 | 76b058813862 |
14 | 348c5536ccad |
15 | 185d48e03e2b |
hex | c44b7a84029 |
13489278566441 has 2 divisors, whose sum is σ = 13489278566442. Its totient is φ = 13489278566440.
The previous prime is 13489278566377. The next prime is 13489278566459. The reversal of 13489278566441 is 14466587298431.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 12385930003225 + 1103348563216 = 3519365^2 + 1050404^2 .
It is a cyclic number.
It is not a de Polignac number, because 13489278566441 - 26 = 13489278566377 is a prime.
It is not a weakly prime, because it can be changed into another prime (13489278566461) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6744639283220 + 6744639283221.
It is an arithmetic number, because the mean of its divisors is an integer number (6744639283221).
Almost surely, 213489278566441 is an apocalyptic number.
It is an amenable number.
13489278566441 is a deficient number, since it is larger than the sum of its proper divisors (1).
13489278566441 is an equidigital number, since it uses as much as digits as its factorization.
13489278566441 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 278691840, while the sum is 68.
The spelling of 13489278566441 in words is "thirteen trillion, four hundred eighty-nine billion, two hundred seventy-eight million, five hundred sixty-six thousand, four hundred forty-one".
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