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134894833 is a prime number
BaseRepresentation
bin10000000101001…
…01010011110001
3100101211100220221
420002211103301
5234013113313
621215133041
73225405253
oct1002452361
9311740827
10134894833
116a165537
1239214181
1321c40738
1413cb5cd3
15bc98c8d
hex80a54f1

134894833 has 2 divisors, whose sum is σ = 134894834. Its totient is φ = 134894832.

The previous prime is 134894821. The next prime is 134894849. The reversal of 134894833 is 338498431.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 134281744 + 613089 = 11588^2 + 783^2 .

It is an emirp because it is prime and its reverse (338498431) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 134894833 - 25 = 134894801 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 134894833.

It is not a weakly prime, because it can be changed into another prime (134894873) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67447416 + 67447417.

It is an arithmetic number, because the mean of its divisors is an integer number (67447417).

Almost surely, 2134894833 is an apocalyptic number.

It is an amenable number.

134894833 is a deficient number, since it is larger than the sum of its proper divisors (1).

134894833 is an equidigital number, since it uses as much as digits as its factorization.

134894833 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 248832, while the sum is 43.

The square root of 134894833 is about 11614.4234897820. The cubic root of 134894833 is about 512.8595397377.

The spelling of 134894833 in words is "one hundred thirty-four million, eight hundred ninety-four thousand, eight hundred thirty-three".