13490223 has 4 divisors (see below), whose sum is σ = 17986968. Its totient is φ = 8993480.

The previous prime is 13490221. The next prime is 13490227. The reversal of 13490223 is 32209431.

13490223 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 32209431 = 3 ⋅10736477.

It is a cyclic number.

It is not a de Polignac number, because 13490223 - 2¹ = 13490221 is a prime.

It is a super-2 number, since 2×13490223² = 363972233179458, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13490193 and 13490202.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13490221) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2248368 + ... + 2248373.

It is an arithmetic number, because the mean of its divisors is an integer number (4496742).

Almost surely, 2^13490223 is an apocalyptic number.

13490223 is a deficient number, since it is larger than the sum of its proper divisors (4496745).

13490223 is an equidigital number, since it uses as much as digits as its factorization.

13490223 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4496744.

The product of its (nonzero) digits is 1296, while the sum is 24.

The square root of 13490223 is about 3672.9038920179. The cubic root of 13490223 is about 238.0526623573.

Adding to 13490223 its reverse (32209431), we get a palindrome (45699654).

The spelling of 13490223 in words is "thirteen million, four hundred ninety thousand, two hundred twenty-three".