Base | Representation |
---|---|
bin | 11110101011000110111101… |
… | …100110010000100111111001 |
3 | 122200122200022101021021021202 |
4 | 132223012331212100213321 |
5 | 120140231000013122244 |
6 | 1154525542033343545 |
7 | 40262323066126253 |
oct | 3653067546204771 |
9 | 580580271237252 |
10 | 134903808723449 |
11 | 39a914250a8a17 |
12 | 13169318707bb5 |
13 | 5a374b3c3991c |
14 | 2545544686cd3 |
15 | 108e25712104e |
hex | 7ab1bd9909f9 |
134903808723449 has 2 divisors, whose sum is σ = 134903808723450. Its totient is φ = 134903808723448.
The previous prime is 134903808723433. The next prime is 134903808723457. The reversal of 134903808723449 is 944327808309431.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 73519169246224 + 61384639477225 = 8574332^2 + 7834835^2 .
It is a cyclic number.
It is not a de Polignac number, because 134903808723449 - 24 = 134903808723433 is a prime.
It is not a weakly prime, because it can be changed into another prime (134903808723419) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67451904361724 + 67451904361725.
It is an arithmetic number, because the mean of its divisors is an integer number (67451904361725).
Almost surely, 2134903808723449 is an apocalyptic number.
It is an amenable number.
134903808723449 is a deficient number, since it is larger than the sum of its proper divisors (1).
134903808723449 is an equidigital number, since it uses as much as digits as its factorization.
134903808723449 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 125411328, while the sum is 65.
The spelling of 134903808723449 in words is "one hundred thirty-four trillion, nine hundred three billion, eight hundred eight million, seven hundred twenty-three thousand, four hundred forty-nine".
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