13491324000 has 1152 divisors, whose sum is σ = 62013579264. Its totient is φ = 2695680000.

The previous prime is 13491323983. The next prime is 13491324037. The reversal of 13491324000 is 42319431.

It is a super-3 number, since 3×13491324000³ (a number of 31 digits) contains 333 as substring.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 191 ways as a sum of consecutive naturals, for example, 85931922 + ... + 85932078.

It is an arithmetic number, because the mean of its divisors is an integer number (53831232).

Almost surely, 2^13491324000 is an apocalyptic number.

13491324000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13491324000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (31006789632).

13491324000 is an abundant number, since it is smaller than the sum of its proper divisors (48522255264).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13491324000 is a wasteful number, since it uses less digits than its factorization.

13491324000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 237 (or 216 counting only the distinct ones).

The product of its (nonzero) digits is 2592, while the sum is 27.

The spelling of 13491324000 in words is "thirteen billion, four hundred ninety-one million, three hundred twenty-four thousand".