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13491433 is a prime number
BaseRepresentation
bin110011011101…
…110011101001
3221101102202201
4303131303221
511423211213
61201100201
7222450424
oct63356351
927342681
1013491433
11768534a
124627661
132a44ac7
141b129bb
1512b76dd
hexcddce9

13491433 has 2 divisors, whose sum is σ = 13491434. Its totient is φ = 13491432.

The previous prime is 13491403. The next prime is 13491437. The reversal of 13491433 is 33419431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13046544 + 444889 = 3612^2 + 667^2 .

It is a cyclic number.

It is not a de Polignac number, because 13491433 - 213 = 13483241 is a prime.

It is not a weakly prime, because it can be changed into another prime (13491437) by changing a digit.

It is a good prime.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6745716 + 6745717.

It is an arithmetic number, because the mean of its divisors is an integer number (6745717).

Almost surely, 213491433 is an apocalyptic number.

It is an amenable number.

13491433 is a deficient number, since it is larger than the sum of its proper divisors (1).

13491433 is an equidigital number, since it uses as much as digits as its factorization.

13491433 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 3888, while the sum is 28.

The square root of 13491433 is about 3673.0686081259. The cubic root of 13491433 is about 238.0597794897.

It can be divided in two parts, 13491 and 433, that added together give a square (13924 = 1182).

The spelling of 13491433 in words is "thirteen million, four hundred ninety-one thousand, four hundred thirty-three".