Base | Representation |
---|---|
bin | 10011101000100001100… |
… | …101001111100001101001 |
3 | 11202222110220002221022202 |
4 | 103220201211033201221 |
5 | 134101111341020433 |
6 | 2511450045025545 |
7 | 166322005326041 |
oct | 23504145174151 |
9 | 4688426087282 |
10 | 1349183141993 |
11 | 48020478a785 |
12 | 1995928552b5 |
13 | 9a2c586101b |
14 | 4942d602721 |
15 | 25166c12ee8 |
hex | 13a2194f869 |
1349183141993 has 2 divisors, whose sum is σ = 1349183141994. Its totient is φ = 1349183141992.
The previous prime is 1349183141983. The next prime is 1349183142061. The reversal of 1349183141993 is 3991413819431.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1221814097449 + 127369044544 = 1105357^2 + 356888^2 .
It is a cyclic number.
It is not a de Polignac number, because 1349183141993 - 28 = 1349183141737 is a prime.
It is not a weakly prime, because it can be changed into another prime (1349183141983) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 674591570996 + 674591570997.
It is an arithmetic number, because the mean of its divisors is an integer number (674591570997).
Almost surely, 21349183141993 is an apocalyptic number.
It is an amenable number.
1349183141993 is a deficient number, since it is larger than the sum of its proper divisors (1).
1349183141993 is an equidigital number, since it uses as much as digits as its factorization.
1349183141993 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 2519424, while the sum is 56.
The spelling of 1349183141993 in words is "one trillion, three hundred forty-nine billion, one hundred eighty-three million, one hundred forty-one thousand, nine hundred ninety-three".
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