Base | Representation |
---|---|
bin | 11001001000010111… |
… | …01110010100110110 |
3 | 1021211021111022211222 |
4 | 30210023232110312 |
5 | 210112420024443 |
6 | 10110443230342 |
7 | 655225503524 |
oct | 144413562466 |
9 | 37737438758 |
10 | 13491954998 |
11 | 57a3947535 |
12 | 27465183b2 |
13 | 137029b032 |
14 | 91dc29314 |
15 | 53e72b468 |
hex | 3242ee536 |
13491954998 has 4 divisors (see below), whose sum is σ = 20237932500. Its totient is φ = 6745977498.
The previous prime is 13491954991. The next prime is 13491955019. The reversal of 13491954998 is 89945919431.
13491954998 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a self number, because there is not a number n which added to its sum of digits gives 13491954998.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13491954991) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3372988748 + ... + 3372988751.
It is an arithmetic number, because the mean of its divisors is an integer number (5059483125).
Almost surely, 213491954998 is an apocalyptic number.
13491954998 is a deficient number, since it is larger than the sum of its proper divisors (6745977502).
13491954998 is an equidigital number, since it uses as much as digits as its factorization.
13491954998 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6745977501.
The product of its digits is 12597120, while the sum is 62.
The spelling of 13491954998 in words is "thirteen billion, four hundred ninety-one million, nine hundred fifty-four thousand, nine hundred ninety-eight".
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