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134939411 is a prime number
BaseRepresentation
bin10000000101100…
…00001100010011
3100101220122001222
420002300030103
5234021030121
621220115255
73225652235
oct1002601423
9311818058
10134939411
116a195a82
1239235b2b
1321c57b09
1413cc8255
15bca70ab
hex80b0313

134939411 has 2 divisors, whose sum is σ = 134939412. Its totient is φ = 134939410.

The previous prime is 134939351. The next prime is 134939429. The reversal of 134939411 is 114939431.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 134939411 - 218 = 134677267 is a prime.

It is not a weakly prime, because it can be changed into another prime (134939471) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67469705 + 67469706.

It is an arithmetic number, because the mean of its divisors is an integer number (67469706).

Almost surely, 2134939411 is an apocalyptic number.

134939411 is a deficient number, since it is larger than the sum of its proper divisors (1).

134939411 is an equidigital number, since it uses as much as digits as its factorization.

134939411 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 11664, while the sum is 35.

The square root of 134939411 is about 11616.3424105869. The cubic root of 134939411 is about 512.9160275318.

The spelling of 134939411 in words is "one hundred thirty-four million, nine hundred thirty-nine thousand, four hundred eleven".