13494023 has 4 divisors (see below), whose sum is σ = 13506528. Its totient is φ = 13481520.

The previous prime is 13493999. The next prime is 13494037. The reversal of 13494023 is 32049431.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 32049431 = 79 ⋅405689.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13494023 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13493983 and 13494001.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13494053) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4463 + ... + 6848.

It is an arithmetic number, because the mean of its divisors is an integer number (3376632).

Almost surely, 2^13494023 is an apocalyptic number.

13494023 is a deficient number, since it is larger than the sum of its proper divisors (12505).

13494023 is a wasteful number, since it uses less digits than its factorization.

13494023 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 12504.

The product of its (nonzero) digits is 2592, while the sum is 26.

The square root of 13494023 is about 3673.4211574498. The cubic root of 13494023 is about 238.0750122521.

The spelling of 13494023 in words is "thirteen million, four hundred ninety-four thousand, twenty-three".