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13493983 is a prime number
BaseRepresentation
bin110011011110…
…011011011111
3221101120021011
4303132123133
511423301413
61201120051
7222461026
oct63363337
927346234
1013493983
117687258
124629027
132a46009
141b138bd
1512b833d
hexcde6df

13493983 has 2 divisors, whose sum is σ = 13493984. Its totient is φ = 13493982.

The previous prime is 13493957. The next prime is 13493989. The reversal of 13493983 is 38939431.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13493983 - 25 = 13493951 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13493989) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6746991 + 6746992.

It is an arithmetic number, because the mean of its divisors is an integer number (6746992).

Almost surely, 213493983 is an apocalyptic number.

13493983 is a deficient number, since it is larger than the sum of its proper divisors (1).

13493983 is an equidigital number, since it uses as much as digits as its factorization.

13493983 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 69984, while the sum is 40.

The square root of 13493983 is about 3673.4157129299. The cubic root of 13493983 is about 238.0747770119.

The spelling of 13493983 in words is "thirteen million, four hundred ninety-three thousand, nine hundred eighty-three".