Base | Representation |
---|---|
bin | 11001001000101000… |
… | …11011100111100011 |
3 | 1021211102210022002021 |
4 | 30210110123213203 |
5 | 210114011101132 |
6 | 10111004202311 |
7 | 655254061531 |
oct | 144424334743 |
9 | 37742708067 |
10 | 13494237667 |
11 | 57a5166539 |
12 | 2747239397 |
13 | 13708ba021 |
14 | 920261151 |
15 | 53ea2c997 |
hex | 32451b9e3 |
13494237667 has 2 divisors, whose sum is σ = 13494237668. Its totient is φ = 13494237666.
The previous prime is 13494237661. The next prime is 13494237707. The reversal of 13494237667 is 76673249431.
13494237667 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13494237667 is a prime.
It is not a weakly prime, because it can be changed into another prime (13494237661) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6747118833 + 6747118834.
It is an arithmetic number, because the mean of its divisors is an integer number (6747118834).
Almost surely, 213494237667 is an apocalyptic number.
13494237667 is a deficient number, since it is larger than the sum of its proper divisors (1).
13494237667 is an equidigital number, since it uses as much as digits as its factorization.
13494237667 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 4572288, while the sum is 52.
The spelling of 13494237667 in words is "thirteen billion, four hundred ninety-four million, two hundred thirty-seven thousand, six hundred sixty-seven".
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