13495080271681 has 2 divisors, whose sum is σ = 13495080271682. Its totient is φ = 13495080271680.

The previous prime is 13495080271633. The next prime is 13495080271721. The reversal of 13495080271681 is 18617208059431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10933544041281 + 2561536230400 = 3306591^2 + 1600480^2 .

It is a cyclic number.

It is not a de Polignac number, because 13495080271681 - 2³⁷ = 13357641318209 is a prime.

It is a super-2 number, since 2×13495080271681² (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13495080271081) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6747540135840 + 6747540135841.

It is an arithmetic number, because the mean of its divisors is an integer number (6747540135841).

It is a 1-persistent number, because it is pandigital, but 2⋅13495080271681 = 26990160543362 is not.

Almost surely, 2^{13495080271681} is an apocalyptic number.

It is an amenable number.

13495080271681 is a deficient number, since it is larger than the sum of its proper divisors (1).

13495080271681 is an equidigital number, since it uses as much as digits as its factorization.

13495080271681 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2903040, while the sum is 55.

The spelling of 13495080271681 in words is "thirteen trillion, four hundred ninety-five billion, eighty million, two hundred seventy-one thousand, six hundred eighty-one".