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134971531200 = 26355211219151
BaseRepresentation
bin111110110110011101…
…1100001111111000000
3110220101101202012100000
41331230323201333000
54202410202444300
6142001032200000
712515502041262
oct1755473417700
9426341665300
10134971531200
1152271a02100
12221a9839000
13c95cb7637c
146765879b32
15379e544c00
hex1f6cee1fc0

134971531200 has 1512 divisors, whose sum is σ = 579418053760. Its totient is φ = 30792960000.

The previous prime is 134971531187. The next prime is 134971531207. The reversal of 134971531200 is 2135179431.

134971531200 is a `hidden beast` number, since 1 + 3 + 497 + 153 + 12 + 0 + 0 = 666.

It is a Harshad number since it is a multiple of its sum of digits (36).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (134971531207) by changing a digit.

It is a polite number, since it can be written in 215 ways as a sum of consecutive naturals, for example, 893851125 + ... + 893851275.

Almost surely, 2134971531200 is an apocalyptic number.

134971531200 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 134971531200, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (289709026880).

134971531200 is an abundant number, since it is smaller than the sum of its proper divisors (444446522560).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

134971531200 is a wasteful number, since it uses less digits than its factorization.

134971531200 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 229 (or 191 counting only the distinct ones).

The product of its (nonzero) digits is 22680, while the sum is 36.

The spelling of 134971531200 in words is "one hundred thirty-four billion, nine hundred seventy-one million, five hundred thirty-one thousand, two hundred".