Base | Representation |
---|---|
bin | 11001001001000000… |
… | …11000000110101001 |
3 | 1021211122200101110121 |
4 | 30210200120012221 |
5 | 210120311302001 |
6 | 10111155243241 |
7 | 655322513014 |
oct | 144440300651 |
9 | 37748611417 |
10 | 13497369001 |
11 | 57a6a05116 |
12 | 27482a9521 |
13 | 137144539c |
14 | 92083837b |
15 | 53ee4a6a1 |
hex | 3248181a9 |
13497369001 has 2 divisors, whose sum is σ = 13497369002. Its totient is φ = 13497369000.
The previous prime is 13497368953. The next prime is 13497369007. The reversal of 13497369001 is 10096379431.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10883705625 + 2613663376 = 104325^2 + 51124^2 .
It is an emirp because it is prime and its reverse (10096379431) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13497369001 is a prime.
It is not a weakly prime, because it can be changed into another prime (13497369007) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6748684500 + 6748684501.
It is an arithmetic number, because the mean of its divisors is an integer number (6748684501).
Almost surely, 213497369001 is an apocalyptic number.
It is an amenable number.
13497369001 is a deficient number, since it is larger than the sum of its proper divisors (1).
13497369001 is an equidigital number, since it uses as much as digits as its factorization.
13497369001 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 122472, while the sum is 43.
The spelling of 13497369001 in words is "thirteen billion, four hundred ninety-seven million, three hundred sixty-nine thousand, one".
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