Base | Representation |
---|---|
bin | 10011101001010001101… |
… | …110001010101000111011 |
3 | 11210001120011211120212121 |
4 | 103221101232022220323 |
5 | 134104240120201033 |
6 | 2512102135422111 |
7 | 166351013235061 |
oct | 23512156125073 |
9 | 4701504746777 |
10 | 1349990787643 |
11 | 480589672923 |
12 | 199779224937 |
13 | 9a3c3c8cc64 |
14 | 494a899c031 |
15 | 251b2a9a62d |
hex | 13a51b8aa3b |
1349990787643 has 2 divisors, whose sum is σ = 1349990787644. Its totient is φ = 1349990787642.
The previous prime is 1349990787599. The next prime is 1349990787647. The reversal of 1349990787643 is 3467870999431.
It is a strong prime.
It is an emirp because it is prime and its reverse (3467870999431) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1349990787643 - 213 = 1349990779451 is a prime.
It is not a weakly prime, because it can be changed into another prime (1349990787647) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 674995393821 + 674995393822.
It is an arithmetic number, because the mean of its divisors is an integer number (674995393822).
Almost surely, 21349990787643 is an apocalyptic number.
1349990787643 is a deficient number, since it is larger than the sum of its proper divisors (1).
1349990787643 is an equidigital number, since it uses as much as digits as its factorization.
1349990787643 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 246903552, while the sum is 70.
The spelling of 1349990787643 in words is "one trillion, three hundred forty-nine billion, nine hundred ninety million, seven hundred eighty-seven thousand, six hundred forty-three".
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