1350015000017 has 2 divisors, whose sum is σ = 1350015000018. Its totient is φ = 1350015000016.

The previous prime is 1350014999999. The next prime is 1350015000053. The reversal of 1350015000017 is 7100005100531.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1346711509441 + 3303490576 = 1160479^2 + 57476^2 .

It is a cyclic number.

It is not a de Polignac number, because 1350015000017 - 2⁸ = 1350014999761 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1350014999956 and 1350015000001.

It is not a weakly prime, because it can be changed into another prime (1350015000517) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 675007500008 + 675007500009.

It is an arithmetic number, because the mean of its divisors is an integer number (675007500009).

Almost surely, 2^{1350015000017} is an apocalyptic number.

It is an amenable number.

1350015000017 is a deficient number, since it is larger than the sum of its proper divisors (1).

1350015000017 is an equidigital number, since it uses as much as digits as its factorization.

1350015000017 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 525, while the sum is 23.

The spelling of 1350015000017 in words is "one trillion, three hundred fifty billion, fifteen million, seventeen", and thus it is an aban number.