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1350015007001 is a prime number
BaseRepresentation
bin10011101001010011001…
…010100011100100011001
311210001121212102001120212
4103221103022203210121
5134104312320211001
62512104402500505
7166351426136333
oct23512312434431
94701555361525
101350015007001
114805a1305221
12199785364735
139a3c8cbca3b
14494abca4453
15251b4c817bb
hex13a532a3919

1350015007001 has 2 divisors, whose sum is σ = 1350015007002. Its totient is φ = 1350015007000.

The previous prime is 1350015006953. The next prime is 1350015007027. The reversal of 1350015007001 is 1007005100531.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1123271424025 + 226743582976 = 1059845^2 + 476176^2 .

It is a cyclic number.

It is not a de Polignac number, because 1350015007001 - 218 = 1350014744857 is a prime.

It is not a weakly prime, because it can be changed into another prime (1350015007031) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 675007503500 + 675007503501.

It is an arithmetic number, because the mean of its divisors is an integer number (675007503501).

Almost surely, 21350015007001 is an apocalyptic number.

It is an amenable number.

1350015007001 is a deficient number, since it is larger than the sum of its proper divisors (1).

1350015007001 is an equidigital number, since it uses as much as digits as its factorization.

1350015007001 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 525, while the sum is 23.

The spelling of 1350015007001 in words is "one trillion, three hundred fifty billion, fifteen million, seven thousand, one".