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135002017 is a prime number
BaseRepresentation
bin10000000101111…
…11011110100001
3100102000210221201
420002333132201
5234030031032
621221321201
73226332613
oct1002773641
9312023851
10135002017
116a229017
1239266201
1321c7a467
1413d02db3
15bcba8e7
hex80bf7a1

135002017 has 2 divisors, whose sum is σ = 135002018. Its totient is φ = 135002016.

The previous prime is 135002009. The next prime is 135002033. The reversal of 135002017 is 710200531.

135002017 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 97535376 + 37466641 = 9876^2 + 6121^2 .

It is a cyclic number.

It is not a de Polignac number, because 135002017 - 23 = 135002009 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 135001985 and 135002003.

It is not a weakly prime, because it can be changed into another prime (135002057) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67501008 + 67501009.

It is an arithmetic number, because the mean of its divisors is an integer number (67501009).

Almost surely, 2135002017 is an apocalyptic number.

It is an amenable number.

135002017 is a deficient number, since it is larger than the sum of its proper divisors (1).

135002017 is an equidigital number, since it uses as much as digits as its factorization.

135002017 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 210, while the sum is 19.

The square root of 135002017 is about 11619.0368361582. The cubic root of 135002017 is about 512.9953388210.

Adding to 135002017 its reverse (710200531), we get a palindrome (845202548).

The spelling of 135002017 in words is "one hundred thirty-five million, two thousand, seventeen".