Base | Representation |
---|---|
bin | 1100010001110100100010… |
… | …0110000001111010111111 |
3 | 1202210121122010110221111120 |
4 | 3010131020212001322333 |
5 | 3232142103313441343 |
6 | 44413541404522023 |
7 | 2562236010543321 |
oct | 304351046017277 |
9 | 52717563427446 |
10 | 13500300140223 |
11 | 4335499527a66 |
12 | 1620547250313 |
13 | 76c0c4052a50 |
14 | 3495bd057611 |
15 | 186291805683 |
hex | c4748981ebf |
13500300140223 has 16 divisors (see below), whose sum is σ = 19385113251840. Its totient is φ = 8307848339424.
The previous prime is 13500300140147. The next prime is 13500300140227. The reversal of 13500300140223 is 32204100300531.
13500300140223 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 13500300140223 - 210 = 13500300139199 is a prime.
It is a super-2 number, since 2×135003001402232 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13500300140193 and 13500300140202.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13500300140227) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 18929890 + ... + 19630112.
It is an arithmetic number, because the mean of its divisors is an integer number (1211569578240).
Almost surely, 213500300140223 is an apocalyptic number.
13500300140223 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
13500300140223 is a deficient number, since it is larger than the sum of its proper divisors (5884813111617).
13500300140223 is a wasteful number, since it uses less digits than its factorization.
13500300140223 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1194598.
The product of its (nonzero) digits is 2160, while the sum is 24.
Adding to 13500300140223 its reverse (32204100300531), we get a palindrome (45704400440754).
The spelling of 13500300140223 in words is "thirteen trillion, five hundred billion, three hundred million, one hundred forty thousand, two hundred twenty-three".
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