Base | Representation |
---|---|
bin | 1100010001110100100011… |
… | …0101101000011010000011 |
3 | 1202210121122102011201122111 |
4 | 3010131020311220122003 |
5 | 3232142110340330034 |
6 | 44413542032320151 |
7 | 2562236060366035 |
oct | 304351065503203 |
9 | 52717572151574 |
10 | 13500304230019 |
11 | 43354a0870762 |
12 | 16205486a3057 |
13 | 76c0c4b55449 |
14 | 3495bd7ddc55 |
15 | 186291d62364 |
hex | c4748d68683 |
13500304230019 has 2 divisors, whose sum is σ = 13500304230020. Its totient is φ = 13500304230018.
The previous prime is 13500304229999. The next prime is 13500304230037. The reversal of 13500304230019 is 91003240300531.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13500304230019 - 213 = 13500304221827 is a prime.
It is a super-2 number, since 2×135003042300192 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13500304230079) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6750152115009 + 6750152115010.
It is an arithmetic number, because the mean of its divisors is an integer number (6750152115010).
Almost surely, 213500304230019 is an apocalyptic number.
13500304230019 is a deficient number, since it is larger than the sum of its proper divisors (1).
13500304230019 is an equidigital number, since it uses as much as digits as its factorization.
13500304230019 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 9720, while the sum is 31.
The spelling of 13500304230019 in words is "thirteen trillion, five hundred billion, three hundred four million, two hundred thirty thousand, nineteen".
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