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13500342953 is a prime number
BaseRepresentation
bin11001001001010111…
…01110001010101001
31021211212021110221222
430210223232022221
5210122041433303
610111343111425
7655360010306
oct144453561251
937755243858
1013500342953
1157a8656529
1227492a2575
131371c46c16
14920db00ad
15540336938
hex324aee2a9

13500342953 has 2 divisors, whose sum is σ = 13500342954. Its totient is φ = 13500342952.

The previous prime is 13500342949. The next prime is 13500343033. The reversal of 13500342953 is 35924300531.

13500342953 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 13475262889 + 25080064 = 116083^2 + 5008^2 .

It is a cyclic number.

It is not a de Polignac number, because 13500342953 - 22 = 13500342949 is a prime.

It is not a weakly prime, because it can be changed into another prime (13500342253) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6750171476 + 6750171477.

It is an arithmetic number, because the mean of its divisors is an integer number (6750171477).

Almost surely, 213500342953 is an apocalyptic number.

It is an amenable number.

13500342953 is a deficient number, since it is larger than the sum of its proper divisors (1).

13500342953 is an equidigital number, since it uses as much as digits as its factorization.

13500342953 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 48600, while the sum is 35.

The spelling of 13500342953 in words is "thirteen billion, five hundred million, three hundred forty-two thousand, nine hundred fifty-three".