Base | Representation |
---|---|
bin | 1100010001110100101101… |
… | …0001101101011110010010 |
3 | 1202210121202021011102202211 |
4 | 3010131023101231132102 |
5 | 3232142201324121414 |
6 | 44413550053302334 |
7 | 2562240065225263 |
oct | 304351321553622 |
9 | 52717667142684 |
10 | 13500345145234 |
11 | 4335511976992 |
12 | 162055a3349aa |
13 | 76c10047c72c |
14 | 3495c501096a |
15 | 1862957453c4 |
hex | c474b46d792 |
13500345145234 has 8 divisors (see below), whose sum is σ = 20254358150460. Its totient is φ = 6748892428416.
The previous prime is 13500345145193. The next prime is 13500345145237. The reversal of 13500345145234 is 43254154300531.
13500345145234 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It can be written as a sum of positive squares in 2 ways, for example, as 12037104119209 + 1463241026025 = 3469453^2 + 1209645^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is not an unprimeable number, because it can be changed into a prime (13500345145237) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 640058919 + ... + 640080010.
Almost surely, 213500345145234 is an apocalyptic number.
13500345145234 is a deficient number, since it is larger than the sum of its proper divisors (6754013005226).
13500345145234 is a wasteful number, since it uses less digits than its factorization.
13500345145234 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1280144204.
The product of its (nonzero) digits is 432000, while the sum is 40.
Adding to 13500345145234 its reverse (43254154300531), we get a palindrome (56754499445765).
The spelling of 13500345145234 in words is "thirteen trillion, five hundred billion, three hundred forty-five million, one hundred forty-five thousand, two hundred thirty-four".
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