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13500345145193 is a prime number
BaseRepresentation
bin1100010001110100101101…
…0001101101011101101001
31202210121202021011102201022
43010131023101231131221
53232142201324121233
644413550053302225
72562240065225204
oct304351321553551
952717667142638
1013500345145193
114335511976955
12162055a334975
1376c10047c6ca
143495c501093b
15186295745398
hexc474b46d769

13500345145193 has 2 divisors, whose sum is σ = 13500345145194. Its totient is φ = 13500345145192.

The previous prime is 13500345145171. The next prime is 13500345145237. The reversal of 13500345145193 is 39154154300531.

It is an a-pointer prime, because the next prime (13500345145237) can be obtained adding 13500345145193 to its sum of digits (44).

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 13226510627929 + 273834517264 = 3636827^2 + 523292^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13500345145193 is a prime.

It is not a weakly prime, because it can be changed into another prime (13500345445193) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6750172572596 + 6750172572597.

It is an arithmetic number, because the mean of its divisors is an integer number (6750172572597).

Almost surely, 213500345145193 is an apocalyptic number.

It is an amenable number.

13500345145193 is a deficient number, since it is larger than the sum of its proper divisors (1).

13500345145193 is an equidigital number, since it uses as much as digits as its factorization.

13500345145193 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 486000, while the sum is 44.

The spelling of 13500345145193 in words is "thirteen trillion, five hundred billion, three hundred forty-five million, one hundred forty-five thousand, one hundred ninety-three".