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13500351454153 is a prime number
BaseRepresentation
bin1100010001110100101110…
…1001110001101111001001
31202210121202201000221222111
43010131023221301233021
53232142204433013103
644413550440422321
72562240202652524
oct304351351615711
952717681027874
1013500351454153
114335515495973
1216205604779a1
1376c10187b215
143495c5bb3bbb
1518629608e86d
hexc474ba71bc9

13500351454153 has 2 divisors, whose sum is σ = 13500351454154. Its totient is φ = 13500351454152.

The previous prime is 13500351454069. The next prime is 13500351454259. The reversal of 13500351454153 is 35145415300531.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 7137890052489 + 6362461401664 = 2671683^2 + 2522392^2 .

It is a cyclic number.

It is not a de Polignac number, because 13500351454153 - 225 = 13500317899721 is a prime.

It is not a weakly prime, because it can be changed into another prime (13500351494153) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6750175727076 + 6750175727077.

It is an arithmetic number, because the mean of its divisors is an integer number (6750175727077).

Almost surely, 213500351454153 is an apocalyptic number.

It is an amenable number.

13500351454153 is a deficient number, since it is larger than the sum of its proper divisors (1).

13500351454153 is an equidigital number, since it uses as much as digits as its factorization.

13500351454153 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 270000, while the sum is 40.

Adding to 13500351454153 its reverse (35145415300531), we get a palindrome (48645766754684).

The spelling of 13500351454153 in words is "thirteen trillion, five hundred billion, three hundred fifty-one million, four hundred fifty-four thousand, one hundred fifty-three".