1350040253 has 4 divisors (see below), whose sum is σ = 1355059260. Its totient is φ = 1345021248.

The previous prime is 1350040249. The next prime is 1350040259. The reversal of 1350040253 is 3520400531.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 328406884 + 1021633369 = 18122^2 + 31963^2 .

It is a cyclic number.

It is not a de Polignac number, because 1350040253 - 2² = 1350040249 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1350040259) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2509100 + ... + 2509637.

It is an arithmetic number, because the mean of its divisors is an integer number (338764815).

Almost surely, 2^1350040253 is an apocalyptic number.

It is an amenable number.

1350040253 is a deficient number, since it is larger than the sum of its proper divisors (5019007).

1350040253 is an equidigital number, since it uses as much as digits as its factorization.

1350040253 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5019006.

The product of its (nonzero) digits is 1800, while the sum is 23.

The square root of 1350040253 is about 36742.8939116124. The cubic root of 1350040253 is about 1105.2204341733.

Adding to 1350040253 its reverse (3520400531), we get a palindrome (4870440784).

The spelling of 1350040253 in words is "one billion, three hundred fifty million, forty thousand, two hundred fifty-three".