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1350053118 = 23275002951
BaseRepresentation
bin101000001111000…
…0010110011111110
310111002100210201100
41100132002303332
510231103144433
6341544153530
745312155631
oct12036026376
93432323640
101350053118
11633084987
123181688a6
131869115cb
14cb42dc18
157d7cab13
hex50782cfe

1350053118 has 12 divisors (see below), whose sum is σ = 2925115128. Its totient is φ = 450017700.

The previous prime is 1350053083. The next prime is 1350053123. The reversal of 1350053118 is 8113500531.

It is a junction number, because it is equal to n+sod(n) for n = 1350053091 and 1350053100.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 37501458 + ... + 37501493.

It is an arithmetic number, because the mean of its divisors is an integer number (243759594).

Almost surely, 21350053118 is an apocalyptic number.

1350053118 is a gapful number since it is divisible by the number (18) formed by its first and last digit.

1350053118 is an abundant number, since it is smaller than the sum of its proper divisors (1575062010).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1350053118 is a wasteful number, since it uses less digits than its factorization.

1350053118 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 75002959 (or 75002956 counting only the distinct ones).

The product of its (nonzero) digits is 1800, while the sum is 27.

The square root of 1350053118 is about 36743.0689790605. The cubic root of 1350053118 is about 1105.2239448379.

Adding to 1350053118 its reverse (8113500531), we get a palindrome (9463553649).

The spelling of 1350053118 in words is "one billion, three hundred fifty million, fifty-three thousand, one hundred eighteen".

Divisors: 1 2 3 6 9 18 75002951 150005902 225008853 450017706 675026559 1350053118