Base | Representation |
---|---|
bin | 111110110111011110… |
… | …1010100000101001011 |
3 | 110220110202202200102121 |
4 | 1331232331110011023 |
5 | 4202442410143341 |
6 | 142004245312111 |
7 | 12516364160152 |
oct | 1755675240513 |
9 | 426422680377 |
10 | 135005552971 |
11 | 5228a12a173 |
12 | 221b9105637 |
13 | c966c28ab3 |
14 | 676a1b4599 |
15 | 37a25154d1 |
hex | 1f6ef5414b |
135005552971 has 2 divisors, whose sum is σ = 135005552972. Its totient is φ = 135005552970.
The previous prime is 135005552939. The next prime is 135005552977. The reversal of 135005552971 is 179255500531.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 135005552971 - 25 = 135005552939 is a prime.
It is not a weakly prime, because it can be changed into another prime (135005552977) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67502776485 + 67502776486.
It is an arithmetic number, because the mean of its divisors is an integer number (67502776486).
Almost surely, 2135005552971 is an apocalyptic number.
135005552971 is a deficient number, since it is larger than the sum of its proper divisors (1).
135005552971 is an equidigital number, since it uses as much as digits as its factorization.
135005552971 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 236250, while the sum is 43.
The spelling of 135005552971 in words is "one hundred thirty-five billion, five million, five hundred fifty-two thousand, nine hundred seventy-one".
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