13501054401 has 4 divisors (see below), whose sum is σ = 18001405872. Its totient is φ = 9000702932.

The previous prime is 13501054397. The next prime is 13501054471. The reversal of 13501054401 is 10445010531.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 10445010531 = 3 ⋅3481670177.

It is a cyclic number.

It is not a de Polignac number, because 13501054401 - 2² = 13501054397 is a prime.

It is a super-2 number, since 2×13501054401² (a number of 21 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (13501054471) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2250175731 + ... + 2250175736.

It is an arithmetic number, because the mean of its divisors is an integer number (4500351468).

Almost surely, 2^13501054401 is an apocalyptic number.

It is an amenable number.

13501054401 is a deficient number, since it is larger than the sum of its proper divisors (4500351471).

13501054401 is an equidigital number, since it uses as much as digits as its factorization.

13501054401 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4500351470.

The product of its (nonzero) digits is 1200, while the sum is 24.

Adding to 13501054401 its reverse (10445010531), we get a palindrome (23946064932).

The spelling of 13501054401 in words is "thirteen billion, five hundred one million, fifty-four thousand, four hundred one".