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13501074103 = 112539483407
BaseRepresentation
bin11001001001011101…
…00000101010110111
31021211220122121220121
430210232200222313
5210122233332403
610111410512411
7655366144036
oct144456405267
937756577817
1013501074103
1157a9005890
122749595707
13137214195a
1492112071d
1554042d3bd
hex324ba0ab7

13501074103 has 8 divisors (see below), whose sum is σ = 14734275840. Its totient is φ = 12268844280.

The previous prime is 13501074079. The next prime is 13501074179. The reversal of 13501074103 is 30147010531.

13501074103 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 13501074103 - 25 = 13501074071 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13501074193) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 213775 + ... + 269632.

It is an arithmetic number, because the mean of its divisors is an integer number (1841784480).

Almost surely, 213501074103 is an apocalyptic number.

13501074103 is a deficient number, since it is larger than the sum of its proper divisors (1233201737).

13501074103 is a wasteful number, since it uses less digits than its factorization.

13501074103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 485957.

The product of its (nonzero) digits is 1260, while the sum is 25.

Adding to 13501074103 its reverse (30147010531), we get a palindrome (43648084634).

The spelling of 13501074103 in words is "thirteen billion, five hundred one million, seventy-four thousand, one hundred three".

Divisors: 1 11 2539 27929 483407 5317477 1227370373 13501074103