13501100141 has 4 divisors (see below), whose sum is σ = 13502511900. Its totient is φ = 13499688384.

The previous prime is 13501100113. The next prime is 13501100143. The reversal of 13501100141 is 14100110531.

13501100141 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 6651054916 + 6850045225 = 81554^2 + 82765^2 .

It is a cyclic number.

It is not a de Polignac number, because 13501100141 - 2²² = 13496905837 is a prime.

It is a super-3 number, since 3×13501100141³ (a number of 31 digits) contains 333 as substring.

It is a Duffinian number.

It is a Curzon number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13501100143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 691436 + ... + 710693.

It is an arithmetic number, because the mean of its divisors is an integer number (3375627975).

Almost surely, 2^13501100141 is an apocalyptic number.

It is an amenable number.

13501100141 is a deficient number, since it is larger than the sum of its proper divisors (1411759).

13501100141 is an equidigital number, since it uses as much as digits as its factorization.

13501100141 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1411758.

The product of its (nonzero) digits is 60, while the sum is 17.

Adding to 13501100141 its reverse (14100110531), we get a palindrome (27601210672).

The spelling of 13501100141 in words is "thirteen billion, five hundred one million, one hundred thousand, one hundred forty-one".